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Smart Automation Adobe Photoshop CC 2019 has a smart and reliable auto-adjustment tool to apply and adjust 388ed7b0c7 Photoshop EXpress Crack + With Key [Updated-2022] Q: C++: uninitialized char array does not throw a warning Assume I have a std::stringstream which contains text and I am using it as if it were a string. I have a char * that is a local variable and so its intial value is whatever the program uses. Then I have an array of char with a known size of how long I know that string should be. When the char * is used to set the internal char array, both the char * (which is zero-initialized) and the array (which is not) are default-constructed, but if I am setting an array of chars, why would I not get a warning saying that the array was not initialized? Why would the array get built, except that some later code later on still uses the value of that char, after it is set by the char * being used? A: I am using it as if it were a string void foo() { std::stringstream ss("test string"); char const* tmp = ss.str().c_str(); char arr[] = "test string"; } Both the char * (which is zero-initialized) and the array (which is not) are default-constructed char arr[] = "test string"; does not default-construct the array. It initializes the array. Array-initialization is more efficient than default-initialization. (Allocated storage in memory is initialized to some known state, whereas zero-initialization requires creating and destroying storage.) Why would I not get a warning saying that the array was not initialized? No, C++ has no notion of initialized array. Why would the array get built, except that some later code later on still uses the value of that char, after it is set by the char * being used? Array-initialization is more efficient than default-initialization, which, if the array was zero-initialized, would require creating the array and invoking default-constructor for each element. It's also safer than default-initialization for non-POD types. If the array was zero-initialized, it would require a default-constructor call (which may invoke placement new, and so if you give your function a strong exception guarantee, you have to be sure it's safe to use it, even What's New in the? Q: MySQL Select only unique ID from same table Tables are something like UID | State | City -------------------------------- 1 | Texas | San Antonio 1 | Colorado| Denver 1 | Arizona| Phoenix And my query is to: SELECT State, City, Count(*) FROM Table1 GROUP BY State, City; The result is: State | City | Count ------------------------------ Texas | San Antonio | 1 Texas | Denver | 1 Colorado | Denver | 1 Arizona | Phoenix | 1 The Count should be 2. i.e it needs to check for duplicates of State and City. From my above table the count should be 1, But It gives as 2. How can I do that? A: You can use the GROUP_CONCAT function : SELECT State, City, Count(*) FROM Table1 GROUP BY State, City A: You can use GROUP_CONCAT to concatenate all states and cities into a comma separated string and then use IN() to check for duplicates. SELECT State, City, Count(*) FROM Table1 GROUP BY State, City HAVING Count(*) > 1 GROUP BY is required in order for the aggregates to count correctly when using the result of a subquery as a HAVING clause. A: I also would do it this way, to give you the idea: SELECT State, City, Count(*) AS cnt FROM Table1 GROUP BY State, City HAVING COUNT(*) > 1 When you group the table, the count of each attribute gets added to the count of the group. If you group the result you get all groups and for each group you get the count of the attributes from the query. By checking for the count > 1, you will get only the groups which have more than 1 member (see the example, the System Requirements: By the time of writing, Shadow of the Tomb Raider is running on the Xbox One X with a GTX 1080, i7-6700k with a 16GB of RAM. The minimum OS is Windows 7/8 with a GTX 1050 Ti and i5-6600k. It will run on a GTX 1060 or better and i5-6500k with 16GB RAM. Old school PC’s can run it at 1080p. 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